3.34 \(\int (c \sin (a+b x))^{2/3} \, dx\)

Optimal. Leaf size=58 \[ \frac {3 \cos (a+b x) (c \sin (a+b x))^{5/3} \, _2F_1\left (\frac {1}{2},\frac {5}{6};\frac {11}{6};\sin ^2(a+b x)\right )}{5 b c \sqrt {\cos ^2(a+b x)}} \]

[Out]

3/5*cos(b*x+a)*hypergeom([1/2, 5/6],[11/6],sin(b*x+a)^2)*(c*sin(b*x+a))^(5/3)/b/c/(cos(b*x+a)^2)^(1/2)

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Rubi [A]  time = 0.01, antiderivative size = 58, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {2643} \[ \frac {3 \cos (a+b x) (c \sin (a+b x))^{5/3} \, _2F_1\left (\frac {1}{2},\frac {5}{6};\frac {11}{6};\sin ^2(a+b x)\right )}{5 b c \sqrt {\cos ^2(a+b x)}} \]

Antiderivative was successfully verified.

[In]

Int[(c*Sin[a + b*x])^(2/3),x]

[Out]

(3*Cos[a + b*x]*Hypergeometric2F1[1/2, 5/6, 11/6, Sin[a + b*x]^2]*(c*Sin[a + b*x])^(5/3))/(5*b*c*Sqrt[Cos[a +
b*x]^2])

Rule 2643

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(Cos[c + d*x]*(b*Sin[c + d*x])^(n + 1)*Hypergeomet
ric2F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2])/(b*d*(n + 1)*Sqrt[Cos[c + d*x]^2]), x] /; FreeQ[{b, c, d, n
}, x] &&  !IntegerQ[2*n]

Rubi steps

\begin {align*} \int (c \sin (a+b x))^{2/3} \, dx &=\frac {3 \cos (a+b x) \, _2F_1\left (\frac {1}{2},\frac {5}{6};\frac {11}{6};\sin ^2(a+b x)\right ) (c \sin (a+b x))^{5/3}}{5 b c \sqrt {\cos ^2(a+b x)}}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 55, normalized size = 0.95 \[ \frac {3 \sqrt {\cos ^2(a+b x)} \tan (a+b x) (c \sin (a+b x))^{2/3} \, _2F_1\left (\frac {1}{2},\frac {5}{6};\frac {11}{6};\sin ^2(a+b x)\right )}{5 b} \]

Antiderivative was successfully verified.

[In]

Integrate[(c*Sin[a + b*x])^(2/3),x]

[Out]

(3*Sqrt[Cos[a + b*x]^2]*Hypergeometric2F1[1/2, 5/6, 11/6, Sin[a + b*x]^2]*(c*Sin[a + b*x])^(2/3)*Tan[a + b*x])
/(5*b)

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fricas [F]  time = 0.45, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\left (c \sin \left (b x + a\right )\right )^{\frac {2}{3}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))^(2/3),x, algorithm="fricas")

[Out]

integral((c*sin(b*x + a))^(2/3), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (c \sin \left (b x + a\right )\right )^{\frac {2}{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))^(2/3),x, algorithm="giac")

[Out]

integrate((c*sin(b*x + a))^(2/3), x)

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maple [F]  time = 0.17, size = 0, normalized size = 0.00 \[ \int \left (c \sin \left (b x +a \right )\right )^{\frac {2}{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*sin(b*x+a))^(2/3),x)

[Out]

int((c*sin(b*x+a))^(2/3),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (c \sin \left (b x + a\right )\right )^{\frac {2}{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))^(2/3),x, algorithm="maxima")

[Out]

integrate((c*sin(b*x + a))^(2/3), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int {\left (c\,\sin \left (a+b\,x\right )\right )}^{2/3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*sin(a + b*x))^(2/3),x)

[Out]

int((c*sin(a + b*x))^(2/3), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (c \sin {\left (a + b x \right )}\right )^{\frac {2}{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))**(2/3),x)

[Out]

Integral((c*sin(a + b*x))**(2/3), x)

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